What are the solutions to the equation solvefor n,2n^2+4n=0 ?

The solutions to the equation solvefor n,2n^2+4n=0 are n=0,n=-2

Find the zeros of solvefor n,2n^2+4n=0

The zeros of solvefor n,2n^2+4n=0 are n=0,n=-2

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solve for

n, 2 n^{2} + 4 n = 0

n = 0, n = - 2

Solution steps

2 n^{2} + 4 n = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

4^{2} - 4 \cdot 2 \cdot 0 = 4

n_{1, 2} = \frac{- 4 \pm 4}{2 \cdot 2}

Separate the solutions

n_{1} = \frac{- 4 + 4}{2 \cdot 2}, n_{2} = \frac{- 4 - 4}{2 \cdot 2}

n = \frac{- 4 + 4}{2 \cdot 2} : 0

n = \frac{- 4 - 4}{2 \cdot 2} : - 2

The solutions to the quadratic equation are:

n = 0, n = - 2

x^{2} + 4 x + 10 = 6

p^{2} - 3 p = 0

1.3 x^{2} + 7 x = 0

4 x^{2} - 90 = 10

x, 2 x^{2} + y^{2} + 3 \cdot x \cdot y = 1

What are the solutions to the equation solvefor n,2n^2+4n=0 ?
The solutions to the equation solvefor n,2n^2+4n=0 are n=0,n=-2
Find the zeros of solvefor n,2n^2+4n=0
The zeros of solvefor n,2n^2+4n=0 are n=0,n=-2