What are the solutions to the equation 2x^2-8x=-6 ?

The solutions to the equation 2x^2-8x=-6 are x=3,x=1

Find the zeros of 2x^2-8x=-6

The zeros of 2x^2-8x=-6 are x=3,x=1

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2 x^{2} - 8 x = - 6

x = 3, x = 1

Solution steps

2 x^{2} - 8 x = - 6

Move

6

to the left side

2 x^{2} - 8 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 2 \cdot 6}{2 \cdot 2}

(- 8)^{2} - 4 \cdot 2 \cdot 6 = 4

x_{1, 2} = \frac{- ( - 8 ) \pm 4}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 4}{2 \cdot 2}, x_{2} = \frac{- ( - 8 ) - 4}{2 \cdot 2}

x = \frac{- ( - 8 ) + 4}{2 \cdot 2} : 3

x = \frac{- ( - 8 ) - 4}{2 \cdot 2} : 1

The solutions to the quadratic equation are:

x = 3, x = 1

- 16 t^{2} + 55 t + 10 = 0

x, x^{2} + y^{2} = C

x, x^{2} - 2 y^{3} + 4 y = 2

20 x^{2} + 11 x - 3 = 0

209 - 120 x + 12 x^{2} = 0

What are the solutions to the equation 2x^2-8x=-6 ?
The solutions to the equation 2x^2-8x=-6 are x=3,x=1
Find the zeros of 2x^2-8x=-6
The zeros of 2x^2-8x=-6 are x=3,x=1