What are the solutions to the equation solvefor x,x^2-2y^3+4y=2 ?

The solutions to the equation solvefor x,x^2-2y^3+4y=2 are x=sqrt(2+2y^3-4y),x=-sqrt(2+2y^3-4y)

Find the zeros of solvefor x,x^2-2y^3+4y=2

The zeros of solvefor x,x^2-2y^3+4y=2 are x=sqrt(2+2y^3-4y),x=-sqrt(2+2y^3-4y)

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solve for

x, x^{2} - 2 y^{3} + 4 y = 2

x = 2 + 2 y^{3} - 4 y, x = - 2 + 2 y^{3} - 4 y

Solution steps

x^{2} - 2 y^{3} + 4 y = 2

Move

2 y^{3}

to the right side

x^{2} + 4 y = 2 + 2 y^{3}

Move

4 y

to the right side

x^{2} = 2 + 2 y^{3} - 4 y

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 2 + 2 y^{3} - 4 y, x = - 2 + 2 y^{3} - 4 y

20 x^{2} + 11 x - 3 = 0

209 - 120 x + 12 x^{2} = 0

x, x^{2} + y^{2} + 2 x + 1 = 0

x, 2 x^{2} - 4 x - 1 = 0

\frac{x ^{2} + 10}{2} = 19

What are the solutions to the equation solvefor x,x^2-2y^3+4y=2 ?
The solutions to the equation solvefor x,x^2-2y^3+4y=2 are x=sqrt(2+2y^3-4y),x=-sqrt(2+2y^3-4y)
Find the zeros of solvefor x,x^2-2y^3+4y=2
The zeros of solvefor x,x^2-2y^3+4y=2 are x=sqrt(2+2y^3-4y),x=-sqrt(2+2y^3-4y)