What are the solutions to the equation -16t^2+55t+10=0 ?

The solutions to the equation -16t^2+55t+10=0 are t=-(-55+sqrt(3665))/(32),t=(55+sqrt(3665))/(32)

Find the zeros of -16t^2+55t+10=0

The zeros of -16t^2+55t+10=0 are t=-(-55+sqrt(3665))/(32),t=(55+sqrt(3665))/(32)

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- 16 t^{2} + 55 t + 10 = 0

t = - \frac{- 55 + 3665}{32}, t = \frac{55 + 3665}{32}

Decimal Notation

t = - 0.17310 \dots, t = 3.61060 \dots

Solution steps

- 16 t^{2} + 55 t + 10 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 55 \pm 5 5 ^{2} - 4 ( - 16 ) \cdot 10}{2 ( - 16 )}

5 5^{2} - 4 (- 16) \cdot 10 = 3665

t_{1, 2} = \frac{- 55 \pm 3665}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 55 + 3665}{2 ( - 16 )}, t_{2} = \frac{- 55 - 3665}{2 ( - 16 )}

t = \frac{- 55 + 3665}{2 ( - 16 )} : - \frac{- 55 + 3665}{32}

t = \frac{- 55 - 3665}{2 ( - 16 )} : \frac{55 + 3665}{32}

The solutions to the quadratic equation are:

t = - \frac{- 55 + 3665}{32}, t = \frac{55 + 3665}{32}

x, x^{2} + y^{2} = C

x, x^{2} - 2 y^{3} + 4 y = 2

20 x^{2} + 11 x - 3 = 0

209 - 120 x + 12 x^{2} = 0

x, x^{2} + y^{2} + 2 x + 1 = 0

What are the solutions to the equation -16t^2+55t+10=0 ?
The solutions to the equation -16t^2+55t+10=0 are t=-(-55+sqrt(3665))/(32),t=(55+sqrt(3665))/(32)
Find the zeros of -16t^2+55t+10=0
The zeros of -16t^2+55t+10=0 are t=-(-55+sqrt(3665))/(32),t=(55+sqrt(3665))/(32)