What are the solutions to the equation (2x+3)^2-14x-21=-6 ?

The solutions to the equation (2x+3)^2-14x-21=-6 are x= 3/2 ,x=-1

Find the zeros of (2x+3)^2-14x-21=-6

The zeros of (2x+3)^2-14x-21=-6 are x= 3/2 ,x=-1

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(2 x + 3)^{2} - 14 x - 21 = - 6

x = \frac{3}{2}, x = - 1

Decimal Notation

x = 1.5, x = - 1

Solution steps

(2 x + 3)^{2} - 14 x - 21 = - 6

Expand

(2 x + 3)^{2} - 14 x - 21 : 4 x^{2} - 2 x - 12

4 x^{2} - 2 x - 12 = - 6

Move

6

to the left side

4 x^{2} - 2 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 4 ( - 6 )}{2 \cdot 4}

(- 2)^{2} - 4 \cdot 4 (- 6) = 10

x_{1, 2} = \frac{- ( - 2 ) \pm 10}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 10}{2 \cdot 4}, x_{2} = \frac{- ( - 2 ) - 10}{2 \cdot 4}

x = \frac{- ( - 2 ) + 10}{2 \cdot 4} : \frac{3}{2}

x = \frac{- ( - 2 ) - 10}{2 \cdot 4} : - 1

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = - 1

x, y^{4} = 4 x^{2} + 6 x y

x, x^{2} + k x + 4 = 0

x^{2} + 8 x + 14 = 23

0 = - (x - 5)^{2} + 9

x^{2} - 2 x - 6

What are the solutions to the equation (2x+3)^2-14x-21=-6 ?
The solutions to the equation (2x+3)^2-14x-21=-6 are x= 3/2 ,x=-1
Find the zeros of (2x+3)^2-14x-21=-6
The zeros of (2x+3)^2-14x-21=-6 are x= 3/2 ,x=-1