What are the solutions to the equation 3x= 1/5 x^2+10 ?

The solutions to the equation 3x= 1/5 x^2+10 are x=10,x=5

Find the zeros of 3x= 1/5 x^2+10

The zeros of 3x= 1/5 x^2+10 are x=10,x=5

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3 x = \frac{1}{5} x^{2} + 10

x = 10, x = 5

Solution steps

3 x = \frac{1}{5} x^{2} + 10

Multiply both sides by

5

15 x = x^{2} + 50

Switch sides

x^{2} + 50 = 15 x

Move

15 x

to the left side

x^{2} + 50 - 15 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 15 x + 50 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 1 \cdot 50}{2 \cdot 1}

(- 15)^{2} - 4 \cdot 1 \cdot 50 = 5

x_{1, 2} = \frac{- ( - 15 ) \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 15 ) + 5}{2 \cdot 1}, x_{2} = \frac{- ( - 15 ) - 5}{2 \cdot 1}

x = \frac{- ( - 15 ) + 5}{2 \cdot 1} : 10

x = \frac{- ( - 15 ) - 5}{2 \cdot 1} : 5

The solutions to the quadratic equation are:

x = 10, x = 5

x^{2} - 18 x - 360 = 0

w, x yz + x z w - yz w + w^{2} = 5

4 x^{2} + 12 x - 3 = 0

(b + 7)^{2} = 8

(1 - x) (1 - x) = 0

What are the solutions to the equation 3x= 1/5 x^2+10 ?
The solutions to the equation 3x= 1/5 x^2+10 are x=10,x=5
Find the zeros of 3x= 1/5 x^2+10
The zeros of 3x= 1/5 x^2+10 are x=10,x=5