What are the solutions to the equation x^2-18x-360=0 ?

The solutions to the equation x^2-18x-360=0 are x=30,x=-12

Find the zeros of x^2-18x-360=0

The zeros of x^2-18x-360=0 are x=30,x=-12

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x^{2} - 18 x - 360 = 0

x = 30, x = - 12

Solution steps

x^{2} - 18 x - 360 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 1 \cdot ( - 360 )}{2 \cdot 1}

(- 18)^{2} - 4 \cdot 1 \cdot (- 360) = 42

x_{1, 2} = \frac{- ( - 18 ) \pm 42}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 42}{2 \cdot 1}, x_{2} = \frac{- ( - 18 ) - 42}{2 \cdot 1}

x = \frac{- ( - 18 ) + 42}{2 \cdot 1} : 30

x = \frac{- ( - 18 ) - 42}{2 \cdot 1} : - 12

The solutions to the quadratic equation are:

x = 30, x = - 12

w, x yz + x z w - yz w + w^{2} = 5

4 x^{2} + 12 x - 3 = 0

(b + 7)^{2} = 8

(1 - x) (1 - x) = 0

x, 4 x^{2} + 4 x y + y^{2} = 21

What are the solutions to the equation x^2-18x-360=0 ?
The solutions to the equation x^2-18x-360=0 are x=30,x=-12
Find the zeros of x^2-18x-360=0
The zeros of x^2-18x-360=0 are x=30,x=-12