What are the solutions to the equation x^2+20x-8=0 ?

The solutions to the equation x^2+20x-8=0 are x=2(3sqrt(3)-5),x=-2(5+3sqrt(3))

Find the zeros of x^2+20x-8=0

The zeros of x^2+20x-8=0 are x=2(3sqrt(3)-5),x=-2(5+3sqrt(3))

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x^{2} + 20 x - 8 = 0

x = 2 (33 - 5), x = - 2 (5 + 33)

Solution steps

x^{2} + 20 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

2 0^{2} - 4 \cdot 1 \cdot (- 8) = 123

x_{1, 2} = \frac{- 20 \pm 12 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 20 + 12 3}{2 \cdot 1}, x_{2} = \frac{- 20 - 12 3}{2 \cdot 1}

x = \frac{- 20 + 12 3}{2 \cdot 1} : 2 (33 - 5)

x = \frac{- 20 - 12 3}{2 \cdot 1} : - 2 (5 + 33)

The solutions to the quadratic equation are:

x = 2 (33 - 5), x = - 2 (5 + 33)

- 2 x^{2} + 8 x + 10 = 0

2 x^{2} = - x - 10

6 x^{2} + 9 = - 55 x

7 = (x - 4)^{2} + 3

3 0^{2} + 1 6^{2} = c^{2}

What are the solutions to the equation x^2+20x-8=0 ?
The solutions to the equation x^2+20x-8=0 are x=2(3sqrt(3)-5),x=-2(5+3sqrt(3))
Find the zeros of x^2+20x-8=0
The zeros of x^2+20x-8=0 are x=2(3sqrt(3)-5),x=-2(5+3sqrt(3))