What are the solutions to the equation 1/20 x^2+4x+100=0 ?

The solutions to the equation 1/20 x^2+4x+100=0 are x=-40+20i,x=-40-20i

Find the zeros of 1/20 x^2+4x+100=0

The zeros of 1/20 x^2+4x+100=0 are x=-40+20i,x=-40-20i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{1}{20} x^{2} + 4 x + 100 = 0

x = - 40 + 20 i, x = - 40 - 20 i

Solution steps

\frac{1}{20} x^{2} + 4 x + 100 = 0

Multiply both sides by

20

x^{2} + 80 x + 2000 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 80 \pm 8 0 ^{2} - 4 \cdot 1 \cdot 2000}{2 \cdot 1}

Simplify

8 0^{2} - 4 \cdot 1 \cdot 2000 : 40 i

x_{1, 2} = \frac{- 80 \pm 40 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 80 + 40 i}{2 \cdot 1}, x_{2} = \frac{- 80 - 40 i}{2 \cdot 1}

x = \frac{- 80 + 40 i}{2 \cdot 1} : - 40 + 20 i

x = \frac{- 80 - 40 i}{2 \cdot 1} : - 40 - 20 i

The solutions to the quadratic equation are:

x = - 40 + 20 i, x = - 40 - 20 i

x^{2} + 20 x - 8 = 0

- 2 x^{2} + 8 x + 10 = 0

2 x^{2} = - x - 10

6 x^{2} + 9 = - 55 x

7 = (x - 4)^{2} + 3

What are the solutions to the equation 1/20 x^2+4x+100=0 ?
The solutions to the equation 1/20 x^2+4x+100=0 are x=-40+20i,x=-40-20i
Find the zeros of 1/20 x^2+4x+100=0
The zeros of 1/20 x^2+4x+100=0 are x=-40+20i,x=-40-20i