What are the solutions to the equation 9x^2+7x-56=0 ?

The solutions to the equation 9x^2+7x-56=0 are x=(-7+sqrt(2065))/(18),x=(-7-sqrt(2065))/(18)

Find the zeros of 9x^2+7x-56=0

The zeros of 9x^2+7x-56=0 are x=(-7+sqrt(2065))/(18),x=(-7-sqrt(2065))/(18)

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9 x^{2} + 7 x - 56 = 0

x = \frac{- 7 + 2065}{18}, x = \frac{- 7 - 2065}{18}

Solution steps

9 x^{2} + 7 x - 56 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 9 ( - 56 )}{2 \cdot 9}

7^{2} - 4 \cdot 9 (- 56) = 2065

x_{1, 2} = \frac{- 7 \pm 2065}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 7 + 2065}{2 \cdot 9}, x_{2} = \frac{- 7 - 2065}{2 \cdot 9}

x = \frac{- 7 + 2065}{2 \cdot 9} : \frac{- 7 + 2065}{18}

x = \frac{- 7 - 2065}{2 \cdot 9} : \frac{- 7 - 2065}{18}

The solutions to the quadratic equation are:

x = \frac{- 7 + 2065}{18}, x = \frac{- 7 - 2065}{18}

5 n^{2} + 19 n + 12 = 0

19 x^{2} = 0

s^{2} - s + 1 = 0

x^{2} + 4^{2} = 6^{2}

32 x^{2} - 6 x + 9 = 0

What are the solutions to the equation 9x^2+7x-56=0 ?
The solutions to the equation 9x^2+7x-56=0 are x=(-7+sqrt(2065))/(18),x=(-7-sqrt(2065))/(18)
Find the zeros of 9x^2+7x-56=0
The zeros of 9x^2+7x-56=0 are x=(-7+sqrt(2065))/(18),x=(-7-sqrt(2065))/(18)