What are the solutions to the equation x^2+289=0 ?

The solutions to the equation x^2+289=0 are x=17i,x=-17i

Find the zeros of x^2+289=0

The zeros of x^2+289=0 are x=17i,x=-17i

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x^{2} + 289 = 0

x = 17 i, x = - 17 i

Solution steps

x^{2} + 289 = 0

Move

289

to the right side

x^{2} = - 289

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 289, x = - - 289

- 289 = 17 i

- - 289 = - 17 i

x = 17 i, x = - 17 i

9 x^{2} + 7 x - 56 = 0

5 n^{2} + 19 n + 12 = 0

19 x^{2} = 0

s^{2} - s + 1 = 0

x^{2} + 4^{2} = 6^{2}

What are the solutions to the equation x^2+289=0 ?
The solutions to the equation x^2+289=0 are x=17i,x=-17i
Find the zeros of x^2+289=0
The zeros of x^2+289=0 are x=17i,x=-17i