What are the solutions to the equation x^2+10x=-12 ?

The solutions to the equation x^2+10x=-12 are x=-5+sqrt(13),x=-5-sqrt(13)

Find the zeros of x^2+10x=-12

The zeros of x^2+10x=-12 are x=-5+sqrt(13),x=-5-sqrt(13)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 10 x = - 12

x = - 5 + 13, x = - 5 - 13

Solution steps

x^{2} + 10 x = - 12

Move

12

to the left side

x^{2} + 10 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 12 = 213

x_{1, 2} = \frac{- 10 \pm 2 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 2 13}{2 \cdot 1}, x_{2} = \frac{- 10 - 2 13}{2 \cdot 1}

x = \frac{- 10 + 2 13}{2 \cdot 1} : - 5 + 13

x = \frac{- 10 - 2 13}{2 \cdot 1} : - 5 - 13

The solutions to the quadratic equation are:

x = - 5 + 13, x = - 5 - 13

x, x^{2} + y^{2} - 3 x + y + 10 = 0

x, x^{2} - y^{2} = 1

- 2 x^{2} + 10 = 0

- \frac{7}{4} x^{2} + \frac{3}{2} x = 0

(x - 5)^{2} = 2 x + 14

What are the solutions to the equation x^2+10x=-12 ?
The solutions to the equation x^2+10x=-12 are x=-5+sqrt(13),x=-5-sqrt(13)
Find the zeros of x^2+10x=-12
The zeros of x^2+10x=-12 are x=-5+sqrt(13),x=-5-sqrt(13)