What are the solutions to the equation solvefor x,x^2-y^2=1 ?

The solutions to the equation solvefor x,x^2-y^2=1 are x=sqrt(1+y^2),x=-sqrt(1+y^2)

Find the zeros of solvefor x,x^2-y^2=1

The zeros of solvefor x,x^2-y^2=1 are x=sqrt(1+y^2),x=-sqrt(1+y^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solve for

x, x^{2} - y^{2} = 1

x = 1 + y^{2}, x = - 1 + y^{2}

Solution steps

x^{2} - y^{2} = 1

Move

y^{2}

to the right side

x^{2} = 1 + y^{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1 + y^{2}, x = - 1 + y^{2}

- 2 x^{2} + 10 = 0

- \frac{7}{4} x^{2} + \frac{3}{2} x = 0

(x - 5)^{2} = 2 x + 14

x^{2} + 1.2 x + 0.56 = 0.91

6 y^{2} - 19 y + 8 = 0

What are the solutions to the equation solvefor x,x^2-y^2=1 ?
The solutions to the equation solvefor x,x^2-y^2=1 are x=sqrt(1+y^2),x=-sqrt(1+y^2)
Find the zeros of solvefor x,x^2-y^2=1
The zeros of solvefor x,x^2-y^2=1 are x=sqrt(1+y^2),x=-sqrt(1+y^2)