What are the solutions to the equation solvefor a,2a^2b=2a^2b(1-2a^3b^2) ?

The solutions to the equation solvefor a,2a^2b=2a^2b(1-2a^3b^2) are a=0;\quad b\ne 0

Find the zeros of solvefor a,2a^2b=2a^2b(1-2a^3b^2)

The zeros of solvefor a,2a^2b=2a^2b(1-2a^3b^2) are a=0;\quad b\ne 0

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solve for

a, 2 a^{2} b = 2 a^{2} b (1 - 2 a^{3} b^{2})

a = 0; b \neq = 0

Solution steps

2 a^{2} b = 2 a^{2} b (1 - 2 a^{3} b^{2})

Move

2 a^{2} b (1 - 2 a^{3} b^{2})

to the left side

2 a^{2} b - 2 a^{2} b (1 - 2 a^{3} b^{2}) = 0

Factor

2 a^{2} b - 2 a^{2} b (1 - 2 a^{3} b^{2}) : 4 a^{5} b^{3}

4 a^{5} b^{3} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

a = 0

The solution is

a = 0; b \neq = 0

2 k (k - 5) = 0

- 3 x^{2} + 4 = 0

- x^{2} - 6 x + 7 = 0

7 x^{2} - 3 x + 5 = 0

8 x^{2} - 17 x + 2 = 0

What are the solutions to the equation solvefor a,2a^2b=2a^2b(1-2a^3b^2) ?
The solutions to the equation solvefor a,2a^2b=2a^2b(1-2a^3b^2) are a=0;\quad b\ne 0
Find the zeros of solvefor a,2a^2b=2a^2b(1-2a^3b^2)
The zeros of solvefor a,2a^2b=2a^2b(1-2a^3b^2) are a=0;\quad b\ne 0