What are the solutions to the equation -4x^2+12x-a=0 ?

The solutions to the equation -4x^2+12x-a=0 are x=-(-3+sqrt(-a+9))/2 ,x=(sqrt(-a+9)+3)/2

Find the zeros of -4x^2+12x-a=0

The zeros of -4x^2+12x-a=0 are x=-(-3+sqrt(-a+9))/2 ,x=(sqrt(-a+9)+3)/2

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- 4 x^{2} + 12 x - a = 0

x = - \frac{- 3 + - a + 9}{2}, x = \frac{- a + 9 + 3}{2}

Solution steps

- 4 x^{2} + 12 x - a = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 ( - 4 ) ( - a )}{2 ( - 4 )}

Simplify

1 2^{2} - 4 (- 4) (- a) : 4 9 - a

x_{1, 2} = \frac{- 12 \pm 4 9 - a}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 12 + 4 9 - a}{2 ( - 4 )}, x_{2} = \frac{- 12 - 4 9 - a}{2 ( - 4 )}

x = \frac{- 12 + 4 9 - a}{2 ( - 4 )} : - \frac{- 3 + - a + 9}{2}

x = \frac{- 12 - 4 9 - a}{2 ( - 4 )} : \frac{- a + 9 + 3}{2}

The solutions to the quadratic equation are:

x = - \frac{- 3 + - a + 9}{2}, x = \frac{- a + 9 + 3}{2}

4 q^{2} + 4 q + 1 = 0

x^{2} - 10 x + 25 = 0

x, 9 x^{2} - 18 x y + 9 y^{2} - x - y = 0

12 x^{2} - 88 x + 96 = 0

2 (x + 3)^{2} - 5 = 14 x + 17

What are the solutions to the equation -4x^2+12x-a=0 ?
The solutions to the equation -4x^2+12x-a=0 are x=-(-3+sqrt(-a+9))/2 ,x=(sqrt(-a+9)+3)/2
Find the zeros of -4x^2+12x-a=0
The zeros of -4x^2+12x-a=0 are x=-(-3+sqrt(-a+9))/2 ,x=(sqrt(-a+9)+3)/2