What are the solutions to the equation k^2-4k+1=-19 ?

The solutions to the equation k^2-4k+1=-19 are k=2+4i,k=2-4i

Find the zeros of k^2-4k+1=-19

The zeros of k^2-4k+1=-19 are k=2+4i,k=2-4i

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k^{2} - 4 k + 1 = - 19

k = 2 + 4 i, k = 2 - 4 i

Solution steps

k^{2} - 4 k + 1 = - 19

Move

19

to the left side

k^{2} - 4 k + 20 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

Simplify

(- 4)^{2} - 4 \cdot 1 \cdot 20 : 8 i

k_{1, 2} = \frac{- ( - 4 ) \pm 8 i}{2 \cdot 1}

Separate the solutions

k_{1} = \frac{- ( - 4 ) + 8 i}{2 \cdot 1}, k_{2} = \frac{- ( - 4 ) - 8 i}{2 \cdot 1}

k = \frac{- ( - 4 ) + 8 i}{2 \cdot 1} : 2 + 4 i

k = \frac{- ( - 4 ) - 8 i}{2 \cdot 1} : 2 - 4 i

The solutions to the quadratic equation are:

k = 2 + 4 i, k = 2 - 4 i

(3 - x)^{2} - (3 + x) - 2 = 0

(2 x + 3)^{2} = (x + 4) (x + 3)

9 x - 8 = x^{2}

x, y^{3} + 3 y^{2} - 9 y = x^{2} + 10 x + 12

x^{2} - 23 x + 44 = - 5 x + 5

What are the solutions to the equation k^2-4k+1=-19 ?
The solutions to the equation k^2-4k+1=-19 are k=2+4i,k=2-4i
Find the zeros of k^2-4k+1=-19
The zeros of k^2-4k+1=-19 are k=2+4i,k=2-4i