What are the solutions to the equation 2w^2+11w-63=0 ?

The solutions to the equation 2w^2+11w-63=0 are w= 7/2 ,w=-9

Find the zeros of 2w^2+11w-63=0

The zeros of 2w^2+11w-63=0 are w= 7/2 ,w=-9

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2 w^{2} + 11 w - 63 = 0

w = \frac{7}{2}, w = - 9

Solution steps

2 w^{2} + 11 w - 63 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 2 ( - 63 )}{2 \cdot 2}

1 1^{2} - 4 \cdot 2 (- 63) = 25

w_{1, 2} = \frac{- 11 \pm 25}{2 \cdot 2}

Separate the solutions

w_{1} = \frac{- 11 + 25}{2 \cdot 2}, w_{2} = \frac{- 11 - 25}{2 \cdot 2}

w = \frac{- 11 + 25}{2 \cdot 2} : \frac{7}{2}

w = \frac{- 11 - 25}{2 \cdot 2} : - 9

The solutions to the quadratic equation are:

w = \frac{7}{2}, w = - 9

1 + 0.2 x - 0.48 x^{2} = 0

x, \frac{1}{2} + \frac{x ^{2}}{32} = R

0 = - 0.3 x^{2} + 22 x + 20

2 x^{2} + 13 x + 18 = 0

x^{2} - 3 + 2 x = 0

What are the solutions to the equation 2w^2+11w-63=0 ?
The solutions to the equation 2w^2+11w-63=0 are w= 7/2 ,w=-9
Find the zeros of 2w^2+11w-63=0
The zeros of 2w^2+11w-63=0 are w= 7/2 ,w=-9