What are the solutions to the equation 1+0.2x-0.48x^2=0 ?

The solutions to the equation 1+0.2x-0.48x^2=0 are x=-5/4 ,x= 5/3

Find the zeros of 1+0.2x-0.48x^2=0

The zeros of 1+0.2x-0.48x^2=0 are x=-5/4 ,x= 5/3

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1 + 0.2 x - 0.48 x^{2} = 0

x = - \frac{5}{4}, x = \frac{5}{3}

Decimal Notation

x = - 1.25, x = 1.66666 \dots

Solution steps

1 + 0.2 x - 0.48 x^{2} = 0

Multiply both sides by

100

100 + 20 x - 48 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 48 x^{2} + 20 x + 100 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 ( - 48 ) \cdot 100}{2 ( - 48 )}

2 0^{2} - 4 (- 48) \cdot 100 = 140

x_{1, 2} = \frac{- 20 \pm 140}{2 ( - 48 )}

Separate the solutions

x_{1} = \frac{- 20 + 140}{2 ( - 48 )}, x_{2} = \frac{- 20 - 140}{2 ( - 48 )}

x = \frac{- 20 + 140}{2 ( - 48 )} : - \frac{5}{4}

x = \frac{- 20 - 140}{2 ( - 48 )} : \frac{5}{3}

The solutions to the quadratic equation are:

x = - \frac{5}{4}, x = \frac{5}{3}

x, \frac{1}{2} + \frac{x ^{2}}{32} = R

0 = - 0.3 x^{2} + 22 x + 20

2 x^{2} + 13 x + 18 = 0

x^{2} - 3 + 2 x = 0

2 x^{2} - 3 x (20) + 50 (20)^{2} = 28000

What are the solutions to the equation 1+0.2x-0.48x^2=0 ?
The solutions to the equation 1+0.2x-0.48x^2=0 are x=-5/4 ,x= 5/3
Find the zeros of 1+0.2x-0.48x^2=0
The zeros of 1+0.2x-0.48x^2=0 are x=-5/4 ,x= 5/3