What are the solutions to the equation solvefor x, 1/2+(x^2)/(32)=R ?

The solutions to the equation solvefor x, 1/2+(x^2)/(32)=R are x=4sqrt(2R-1),x=-4sqrt(2R-1)

Find the zeros of solvefor x, 1/2+(x^2)/(32)=R

The zeros of solvefor x, 1/2+(x^2)/(32)=R are x=4sqrt(2R-1),x=-4sqrt(2R-1)

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solve for

x, \frac{1}{2} + \frac{x ^{2}}{32} = R

x = 4 2 R - 1, x = - 4 2 R - 1

Solution steps

\frac{1}{2} + \frac{x ^{2}}{32} = R

Move

\frac{1}{2}

to the right side

\frac{x ^{2}}{32} = R - \frac{1}{2}

Multiply both sides by

32

x^{2} = 32 R - 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 32 R - 16, x = - 32 R - 16

Simplify

32 R - 16 : 4 2 R - 1

Simplify

- 32 R - 16 : - 4 2 R - 1

x = 4 2 R - 1, x = - 4 2 R - 1

0 = - 0.3 x^{2} + 22 x + 20

2 x^{2} + 13 x + 18 = 0

x^{2} - 3 + 2 x = 0

2 x^{2} - 3 x (20) + 50 (20)^{2} = 28000

y, x^{3} - 2 x^{2} y + 3 x y^{2} = 38

What are the solutions to the equation solvefor x, 1/2+(x^2)/(32)=R ?
The solutions to the equation solvefor x, 1/2+(x^2)/(32)=R are x=4sqrt(2R-1),x=-4sqrt(2R-1)
Find the zeros of solvefor x, 1/2+(x^2)/(32)=R
The zeros of solvefor x, 1/2+(x^2)/(32)=R are x=4sqrt(2R-1),x=-4sqrt(2R-1)