What are the solutions to the equation 0=-0.3x^2+22x+20 ?

The solutions to the equation 0=-0.3x^2+22x+20 are x=-(10(sqrt(127)-11))/3 ,x=(10(11+sqrt(127)))/3

Find the zeros of 0=-0.3x^2+22x+20

The zeros of 0=-0.3x^2+22x+20 are x=-(10(sqrt(127)-11))/3 ,x=(10(11+sqrt(127)))/3

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0 = - 0.3 x^{2} + 22 x + 20

x = - \frac{10 ( 127 - 11 )}{3}, x = \frac{10 ( 11 + 127 )}{3}

Solution steps

0 = - 0.3 x^{2} + 22 x + 20

Multiply both sides by

10

0 = - 3 x^{2} + 220 x + 200

Switch sides

- 3 x^{2} + 220 x + 200 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 220 \pm 22 0 ^{2} - 4 ( - 3 ) \cdot 200}{2 ( - 3 )}

22 0^{2} - 4 (- 3) \cdot 200 = 20127

x_{1, 2} = \frac{- 220 \pm 20 127}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 220 + 20 127}{2 ( - 3 )}, x_{2} = \frac{- 220 - 20 127}{2 ( - 3 )}

x = \frac{- 220 + 20 127}{2 ( - 3 )} : - \frac{10 ( 127 - 11 )}{3}

x = \frac{- 220 - 20 127}{2 ( - 3 )} : \frac{10 ( 11 + 127 )}{3}

The solutions to the quadratic equation are:

x = - \frac{10 ( 127 - 11 )}{3}, x = \frac{10 ( 11 + 127 )}{3}

2 x^{2} + 13 x + 18 = 0

x^{2} - 3 + 2 x = 0

2 x^{2} - 3 x (20) + 50 (20)^{2} = 28000

y, x^{3} - 2 x^{2} y + 3 x y^{2} = 38

2 4^{2} + b^{2} = 2 6^{2}

What are the solutions to the equation 0=-0.3x^2+22x+20 ?
The solutions to the equation 0=-0.3x^2+22x+20 are x=-(10(sqrt(127)-11))/3 ,x=(10(11+sqrt(127)))/3
Find the zeros of 0=-0.3x^2+22x+20
The zeros of 0=-0.3x^2+22x+20 are x=-(10(sqrt(127)-11))/3 ,x=(10(11+sqrt(127)))/3