What are the solutions to the equation 5x^2-50x+120=0 ?

The solutions to the equation 5x^2-50x+120=0 are x=6,x=4

Find the zeros of 5x^2-50x+120=0

The zeros of 5x^2-50x+120=0 are x=6,x=4

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5 x^{2} - 50 x + 120 = 0

x = 6, x = 4

Solution steps

5 x^{2} - 50 x + 120 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 50 ) \pm ( - 50 ) ^{2} - 4 \cdot 5 \cdot 120}{2 \cdot 5}

(- 50)^{2} - 4 \cdot 5 \cdot 120 = 10

x_{1, 2} = \frac{- ( - 50 ) \pm 10}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 50 ) + 10}{2 \cdot 5}, x_{2} = \frac{- ( - 50 ) - 10}{2 \cdot 5}

x = \frac{- ( - 50 ) + 10}{2 \cdot 5} : 6

x = \frac{- ( - 50 ) - 10}{2 \cdot 5} : 4

The solutions to the quadratic equation are:

x = 6, x = 4

x^{2} + 2 x + 7

0 = 9 x^{2}

5 + 81 x^{2} = 21

5 x^{2} + 4 x + 9 = 0

2 x^{2} - x = - 8

What are the solutions to the equation 5x^2-50x+120=0 ?
The solutions to the equation 5x^2-50x+120=0 are x=6,x=4
Find the zeros of 5x^2-50x+120=0
The zeros of 5x^2-50x+120=0 are x=6,x=4