What are the solutions to the equation 2(x+4)^2=24 ?

The solutions to the equation 2(x+4)^2=24 are x=2sqrt(3)-4,x=-2sqrt(3)-4

Find the zeros of 2(x+4)^2=24

The zeros of 2(x+4)^2=24 are x=2sqrt(3)-4,x=-2sqrt(3)-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 (x + 4)^{2} = 24

x = 23 - 4, x = - 23 - 4

Decimal Notation

x = - 0.53589 \dots, x = - 7.46410 \dots

Solution steps

2 (x + 4)^{2} = 24

Divide both sides by

2

(x + 4)^{2} = 12

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 4 = 12 : x = 23 - 4

Solve

x + 4 = - 12 : x = - 23 - 4

The solutions to the quadratic equation are:

x = 23 - 4, x = - 23 - 4

x^{2} + 5.1 \cdot 1 0^{- 4} x - (0.0001 \cdot 5.1 \cdot 1 0^{- 4}) = 0

2 s^{2} - 21 s + 49 = 0

5 x^{2} - 25 x + 3 = 0

n^{2} - n - 240 = 0

z^{2} + 14 z + 45 = 0

What are the solutions to the equation 2(x+4)^2=24 ?
The solutions to the equation 2(x+4)^2=24 are x=2sqrt(3)-4,x=-2sqrt(3)-4
Find the zeros of 2(x+4)^2=24
The zeros of 2(x+4)^2=24 are x=2sqrt(3)-4,x=-2sqrt(3)-4