What are the solutions to the equation (r+3/4)^2= 1/16 ?

The solutions to the equation (r+3/4)^2= 1/16 are r=-1/2 ,r=-1

Find the zeros of (r+3/4)^2= 1/16

The zeros of (r+3/4)^2= 1/16 are r=-1/2 ,r=-1

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(r + \frac{3}{4})^{2} = \frac{1}{16}

r = - \frac{1}{2}, r = - 1

Decimal Notation

r = - 0.5, r = - 1

Solution steps

(r + \frac{3}{4})^{2} = \frac{1}{16}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

r + \frac{3}{4} = \frac{1}{16} : r = - \frac{1}{2}

Solve

r + \frac{3}{4} = - \frac{1}{16} : r = - 1

The solutions to the quadratic equation are:

r = - \frac{1}{2}, r = - 1

- 6 x^{2} + 600 = 0

x^{2} + 16 x - 4 = 0

9 x^{2} - 12 x + 3 = 0

3 y^{2} + 4 y = 15

t^{2} - 3 t - 10 = 0

What are the solutions to the equation (r+3/4)^2= 1/16 ?
The solutions to the equation (r+3/4)^2= 1/16 are r=-1/2 ,r=-1
Find the zeros of (r+3/4)^2= 1/16
The zeros of (r+3/4)^2= 1/16 are r=-1/2 ,r=-1