What are the solutions to the equation factor 3x^2-2x-5=0 ?

The solutions to the equation factor 3x^2-2x-5=0 are x=-1,x= 5/3

Find the zeros of factor 3x^2-2x-5=0

The zeros of factor 3x^2-2x-5=0 are x=-1,x= 5/3

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3 x^{2} - 2 x - 5 = 0

x = - 1, x = \frac{5}{3}

Decimal Notation

x = - 1, x = 1.66666 \dots

Solution steps

3 x^{2} - 2 x - 5 = 0

Factor

3 x^{2} - 2 x - 5 : (x + 1) (3 x - 5)

(x + 1) (3 x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or 3 x - 5 = 0

Solve

x + 1 = 0 : x = - 1

Solve

3 x - 5 = 0 : x = \frac{5}{3}

The solutions to the quadratic equation are:

x = - 1, x = \frac{5}{3}

(2 x - 3)^{2} + 6 = 0

x^{2} + (\frac{2 x}{3})^{2} - 4 = 0

x, (x^{2} + 2 y) (x^{2} - 3 y) = x^{4} - 6 y^{2}

3 x^{2} + 7 x

x, x^{2} + 4 x y - 3 y^{2} + x + 2 y - 6 = 0

What are the solutions to the equation factor 3x^2-2x-5=0 ?
The solutions to the equation factor 3x^2-2x-5=0 are x=-1,x= 5/3
Find the zeros of factor 3x^2-2x-5=0
The zeros of factor 3x^2-2x-5=0 are x=-1,x= 5/3