What are the solutions to the equation (2x-3)^2+6=0 ?

The solutions to the equation (2x-3)^2+6=0 are x= 3/2+isqrt(3/2),x= 3/2-isqrt(3/2)

Find the zeros of (2x-3)^2+6=0

The zeros of (2x-3)^2+6=0 are x= 3/2+isqrt(3/2),x= 3/2-isqrt(3/2)

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(2 x - 3)^{2} + 6 = 0

x = \frac{3}{2} + i \frac{3}{2}, x = \frac{3}{2} - i \frac{3}{2}

Solution steps

(2 x - 3)^{2} + 6 = 0

Move

6

to the right side

(2 x - 3)^{2} = - 6

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x - 3 = - 6 : x = \frac{3}{2} + i \frac{3}{2}

Solve

2 x - 3 = - - 6 : x = \frac{3}{2} - i \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{3}{2} + i \frac{3}{2}, x = \frac{3}{2} - i \frac{3}{2}

x^{2} + (\frac{2 x}{3})^{2} - 4 = 0

x, (x^{2} + 2 y) (x^{2} - 3 y) = x^{4} - 6 y^{2}

3 x^{2} + 7 x

x, x^{2} + 4 x y - 3 y^{2} + x + 2 y - 6 = 0

\frac{k ^{2}}{1.2} - 7 = 23

What are the solutions to the equation (2x-3)^2+6=0 ?
The solutions to the equation (2x-3)^2+6=0 are x= 3/2+isqrt(3/2),x= 3/2-isqrt(3/2)
Find the zeros of (2x-3)^2+6=0
The zeros of (2x-3)^2+6=0 are x= 3/2+isqrt(3/2),x= 3/2-isqrt(3/2)