What are the solutions to the equation 3s^2+36s+80=0 ?

The solutions to the equation 3s^2+36s+80=0 are s=(2(sqrt(21)-9))/3 ,s=-(2(9+sqrt(21)))/3

Find the zeros of 3s^2+36s+80=0

The zeros of 3s^2+36s+80=0 are s=(2(sqrt(21)-9))/3 ,s=-(2(9+sqrt(21)))/3

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3 s^{2} + 36 s + 80 = 0

s = \frac{2 ( 21 - 9 )}{3}, s = - \frac{2 ( 9 + 21 )}{3}

Decimal Notation

s = - 2.94494 \dots, s = - 9.05505 \dots

Solution steps

3 s^{2} + 36 s + 80 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 36 \pm 3 6 ^{2} - 4 \cdot 3 \cdot 80}{2 \cdot 3}

3 6^{2} - 4 \cdot 3 \cdot 80 = 421

s_{1, 2} = \frac{- 36 \pm 4 21}{2 \cdot 3}

Separate the solutions

s_{1} = \frac{- 36 + 4 21}{2 \cdot 3}, s_{2} = \frac{- 36 - 4 21}{2 \cdot 3}

s = \frac{- 36 + 4 21}{2 \cdot 3} : \frac{2 ( 21 - 9 )}{3}

s = \frac{- 36 - 4 21}{2 \cdot 3} : - \frac{2 ( 9 + 21 )}{3}

The solutions to the quadratic equation are:

s = \frac{2 ( 21 - 9 )}{3}, s = - \frac{2 ( 9 + 21 )}{3}

m^{2} - 9 m + 14 = 0

m^{2} - 2 m - 16 = 0

x^{2} - 4 x - 7 = 0

x^{2} + 10 x + 23 = 0

x, z = 2 x + 4 y - x^{2} - y^{2} - 3

What are the solutions to the equation 3s^2+36s+80=0 ?
The solutions to the equation 3s^2+36s+80=0 are s=(2(sqrt(21)-9))/3 ,s=-(2(9+sqrt(21)))/3
Find the zeros of 3s^2+36s+80=0
The zeros of 3s^2+36s+80=0 are s=(2(sqrt(21)-9))/3 ,s=-(2(9+sqrt(21)))/3