What are the solutions to the equation factor 3x^2+2x-8=0 ?

The solutions to the equation factor 3x^2+2x-8=0 are x= 4/3 ,x=-2

Find the zeros of factor 3x^2+2x-8=0

The zeros of factor 3x^2+2x-8=0 are x= 4/3 ,x=-2

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3 x^{2} + 2 x - 8 = 0

x = \frac{4}{3}, x = - 2

Decimal Notation

x = 1.33333 \dots, x = - 2

Solution steps

3 x^{2} + 2 x - 8 = 0

Factor

3 x^{2} + 2 x - 8 : (3 x - 4) (x + 2)

(3 x - 4) (x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x - 4 = 0 or x + 2 = 0

Solve

3 x - 4 = 0 : x = \frac{4}{3}

Solve

x + 2 = 0 : x = - 2

The solutions to the quadratic equation are:

x = \frac{4}{3}, x = - 2

12 x^{2} + 13 x - 35 = 0

a^{2} = - 1, 0 y (a) a^{10} = 24

0 = 3 x^{2} - 10 x + 4

3 x^{2} - 36 = 3 x

x, (x + 2)^{2} + (y + 1)^{2} = 0

What are the solutions to the equation factor 3x^2+2x-8=0 ?
The solutions to the equation factor 3x^2+2x-8=0 are x= 4/3 ,x=-2
Find the zeros of factor 3x^2+2x-8=0
The zeros of factor 3x^2+2x-8=0 are x= 4/3 ,x=-2