What are the solutions to the equation solvefor x,x^2+2x=8 ?

The solutions to the equation solvefor x,x^2+2x=8 are x=2,x=-4

Find the zeros of solvefor x,x^2+2x=8

The zeros of solvefor x,x^2+2x=8 are x=2,x=-4

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x, x^{2} + 2 x = 8

x = 2, x = - 4

Solution steps

x^{2} + 2 x = 8

Move

8

to the left side

x^{2} + 2 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 8) = 6

x_{1, 2} = \frac{- 2 \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 6}{2 \cdot 1}, x_{2} = \frac{- 2 - 6}{2 \cdot 1}

x = \frac{- 2 + 6}{2 \cdot 1} : 2

x = \frac{- 2 - 6}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 2, x = - 4

(x + 1)^{2} - 15 = 1

x^{2} + 2 x + 11 = - 4 x + 2

h^{2} = 1 3^{2} + 1 6^{2}

\frac{5}{3} x^{2} - x = \frac{1}{3}

x^{2} - 4 x - 25 = 0

What are the solutions to the equation solvefor x,x^2+2x=8 ?
The solutions to the equation solvefor x,x^2+2x=8 are x=2,x=-4
Find the zeros of solvefor x,x^2+2x=8
The zeros of solvefor x,x^2+2x=8 are x=2,x=-4