What are the solutions to the equation x^2+2x+11=-4x+2 ?

The solutions to the equation x^2+2x+11=-4x+2 are x=-3

Find the zeros of x^2+2x+11=-4x+2

The zeros of x^2+2x+11=-4x+2 are x=-3

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x^{2} + 2 x + 11 = - 4 x + 2

x = - 3

Solution steps

x^{2} + 2 x + 11 = - 4 x + 2

Move

2

to the left side

x^{2} + 2 x + 9 = - 4 x

Move

4 x

to the left side

x^{2} + 6 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 9 = 0

x_{1, 2} = \frac{- 6 \pm 0}{2 \cdot 1}

x = \frac{- 6}{2 \cdot 1}

\frac{- 6}{2 \cdot 1} = - 3

x = - 3

The solution to the quadratic equation is:

x = - 3

h^{2} = 1 3^{2} + 1 6^{2}

\frac{5}{3} x^{2} - x = \frac{1}{3}

x^{2} - 4 x - 25 = 0

- x^{2} - 13 x - 18 = - 3 x

\frac{41}{144} x^{2} + 1 = \frac{60}{7} x - \frac{444}{7}

What are the solutions to the equation x^2+2x+11=-4x+2 ?
The solutions to the equation x^2+2x+11=-4x+2 are x=-3
Find the zeros of x^2+2x+11=-4x+2
The zeros of x^2+2x+11=-4x+2 are x=-3