What are the solutions to the equation 7x^2-2x-2=0 ?

The solutions to the equation 7x^2-2x-2=0 are x=(1+sqrt(15))/7 ,x=(1-sqrt(15))/7

Find the zeros of 7x^2-2x-2=0

The zeros of 7x^2-2x-2=0 are x=(1+sqrt(15))/7 ,x=(1-sqrt(15))/7

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7 x^{2} - 2 x - 2 = 0

x = \frac{1 + 15}{7}, x = \frac{1 - 15}{7}

Decimal Notation

x = 0.69614 \dots, x = - 0.41042 \dots

Solution steps

7 x^{2} - 2 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 7 ( - 2 )}{2 \cdot 7}

(- 2)^{2} - 4 \cdot 7 (- 2) = 215

x_{1, 2} = \frac{- ( - 2 ) \pm 2 15}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 15}{2 \cdot 7}, x_{2} = \frac{- ( - 2 ) - 2 15}{2 \cdot 7}

x = \frac{- ( - 2 ) + 2 15}{2 \cdot 7} : \frac{1 + 15}{7}

x = \frac{- ( - 2 ) - 2 15}{2 \cdot 7} : \frac{1 - 15}{7}

The solutions to the quadratic equation are:

x = \frac{1 + 15}{7}, x = \frac{1 - 15}{7}

(5 - x) (- 4 - x) + 18 = 0

x^{2} - 12 + 26 = 0

2 a^{2} - 8 a = 0

- x^{2} - 2 - x = - 4 - 2 x^{2} + 5 x

2 5^{2} = x^{2} + 7^{2}

What are the solutions to the equation 7x^2-2x-2=0 ?
The solutions to the equation 7x^2-2x-2=0 are x=(1+sqrt(15))/7 ,x=(1-sqrt(15))/7
Find the zeros of 7x^2-2x-2=0
The zeros of 7x^2-2x-2=0 are x=(1+sqrt(15))/7 ,x=(1-sqrt(15))/7