What are the solutions to the equation k^2-8k-16=0 ?

The solutions to the equation k^2-8k-16=0 are k=4(1+sqrt(2)),k=4(1-sqrt(2))

Find the zeros of k^2-8k-16=0

The zeros of k^2-8k-16=0 are k=4(1+sqrt(2)),k=4(1-sqrt(2))

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k^{2} - 8 k - 16 = 0

k = 4 (1 + 2), k = 4 (1 - 2)

Decimal Notation

k = 9.65685 \dots, k = - 1.65685 \dots

Solution steps

k^{2} - 8 k - 16 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot ( - 16 )}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot (- 16) = 82

k_{1, 2} = \frac{- ( - 8 ) \pm 8 2}{2 \cdot 1}

Separate the solutions

k_{1} = \frac{- ( - 8 ) + 8 2}{2 \cdot 1}, k_{2} = \frac{- ( - 8 ) - 8 2}{2 \cdot 1}

k = \frac{- ( - 8 ) + 8 2}{2 \cdot 1} : 4 (1 + 2)

k = \frac{- ( - 8 ) - 8 2}{2 \cdot 1} : 4 (1 - 2)

The solutions to the quadratic equation are:

k = 4 (1 + 2), k = 4 (1 - 2)

- 3 (x + 5)^{2} + 4 = - 23

(s^{2} + 4 s + 4) = 0

4 x (x - b) + b^{2} = 4 m^{2}

4 x^{2} - 22 + 3 x = 0

x^{2} + 38 x = 0

What are the solutions to the equation k^2-8k-16=0 ?
The solutions to the equation k^2-8k-16=0 are k=4(1+sqrt(2)),k=4(1-sqrt(2))
Find the zeros of k^2-8k-16=0
The zeros of k^2-8k-16=0 are k=4(1+sqrt(2)),k=4(1-sqrt(2))