What are the solutions to the equation (s^2+4s+4)=0 ?

The solutions to the equation (s^2+4s+4)=0 are s=-2

Find the zeros of (s^2+4s+4)=0

The zeros of (s^2+4s+4)=0 are s=-2

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(s^{2} + 4 s + 4) = 0

s = - 2

Solution steps

(s^{2} + 4 s + 4) = 0

Refine

s^{2} + 4 s + 4 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 4 = 0

s_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 1}

s = \frac{- 4}{2 \cdot 1}

\frac{- 4}{2 \cdot 1} = - 2

s = - 2

The solution to the quadratic equation is:

s = - 2

4 x (x - b) + b^{2} = 4 m^{2}

4 x^{2} - 22 + 3 x = 0

x^{2} + 38 x = 0

4 x = - 2 x^{2} + 3

(5 x - 2)^{2} + 35 x - 14 = - 12

What are the solutions to the equation (s^2+4s+4)=0 ?
The solutions to the equation (s^2+4s+4)=0 are s=-2
Find the zeros of (s^2+4s+4)=0
The zeros of (s^2+4s+4)=0 are s=-2