What are the solutions to the equation (y-5)^2=0 ?

The solutions to the equation (y-5)^2=0 are y=5

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(y-5)^2=0

(y - 5)^{2} = 0

y = 5

Solution steps

(y - 5)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

y - 5 = 0 : y = 5

The solution to the quadratic equation is:

y = 5

4 x^{2} + 8 x - 20 = 0

x, (x + y)^{2} = 9

p, x^{2} + 2 x p + 25 p^{2} = 74500

4 b^{2} - 9 = 71

25 q^{2} + 40 q + 16 = 0

What are the solutions to the equation (y-5)^2=0 ?
The solutions to the equation (y-5)^2=0 are y=5
Find the zeros of (y-5)^2=0
The zeros of (y-5)^2=0 are y=5