What are the solutions to the equation 4b^2-9=71 ?

The solutions to the equation 4b^2-9=71 are b=2sqrt(5),b=-2sqrt(5)

Find the zeros of 4b^2-9=71

The zeros of 4b^2-9=71 are b=2sqrt(5),b=-2sqrt(5)

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4 b^{2} - 9 = 71

b = 25, b = - 25

Decimal Notation

b = 4.47213 \dots, b = - 4.47213 \dots

Solution steps

4 b^{2} - 9 = 71

Move

9

to the right side

4 b^{2} = 80

Divide both sides by

4

b^{2} = 20

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 20, b = - 20

20 = 25

- 20 = - 25

b = 25, b = - 25

25 q^{2} + 40 q + 16 = 0

x^{(2)} + 11 x + 24 = 0

5 x^{2} + 4 = 3

5 x^{2} - 1 = 3 x^{2}

x, 4 x^{2} + x y = 16

What are the solutions to the equation 4b^2-9=71 ?
The solutions to the equation 4b^2-9=71 are b=2sqrt(5),b=-2sqrt(5)
Find the zeros of 4b^2-9=71
The zeros of 4b^2-9=71 are b=2sqrt(5),b=-2sqrt(5)