What are the solutions to the equation 4x^2+8x-20=0 ?

The solutions to the equation 4x^2+8x-20=0 are x=-1+sqrt(6),x=-1-sqrt(6)

Find the zeros of 4x^2+8x-20=0

The zeros of 4x^2+8x-20=0 are x=-1+sqrt(6),x=-1-sqrt(6)

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4 x^{2} + 8 x - 20 = 0

x = - 1 + 6, x = - 1 - 6

Decimal Notation

x = 1.44948 \dots, x = - 3.44948 \dots

Solution steps

4 x^{2} + 8 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 4 ( - 20 )}{2 \cdot 4}

8^{2} - 4 \cdot 4 (- 20) = 86

x_{1, 2} = \frac{- 8 \pm 8 6}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 8 + 8 6}{2 \cdot 4}, x_{2} = \frac{- 8 - 8 6}{2 \cdot 4}

x = \frac{- 8 + 8 6}{2 \cdot 4} : - 1 + 6

x = \frac{- 8 - 8 6}{2 \cdot 4} : - 1 - 6

The solutions to the quadratic equation are:

x = - 1 + 6, x = - 1 - 6

x, (x + y)^{2} = 9

p, x^{2} + 2 x p + 25 p^{2} = 74500

4 b^{2} - 9 = 71

25 q^{2} + 40 q + 16 = 0

x^{(2)} + 11 x + 24 = 0

What are the solutions to the equation 4x^2+8x-20=0 ?
The solutions to the equation 4x^2+8x-20=0 are x=-1+sqrt(6),x=-1-sqrt(6)
Find the zeros of 4x^2+8x-20=0
The zeros of 4x^2+8x-20=0 are x=-1+sqrt(6),x=-1-sqrt(6)