What are the solutions to the equation 3x^2-33=18x ?

The solutions to the equation 3x^2-33=18x are x=3+2sqrt(5),x=3-2sqrt(5)

Find the zeros of 3x^2-33=18x

The zeros of 3x^2-33=18x are x=3+2sqrt(5),x=3-2sqrt(5)

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3 x^{2} - 33 = 18 x

x = 3 + 25, x = 3 - 25

Decimal Notation

x = 7.47213 \dots, x = - 1.47213 \dots

Solution steps

3 x^{2} - 33 = 18 x

Move

18 x

to the left side

3 x^{2} - 33 - 18 x = 0

Write in the standard form

a x^{2} + b x + c = 0

3 x^{2} - 18 x - 33 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 3 ( - 33 )}{2 \cdot 3}

(- 18)^{2} - 4 \cdot 3 (- 33) = 125

x_{1, 2} = \frac{- ( - 18 ) \pm 12 5}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 12 5}{2 \cdot 3}, x_{2} = \frac{- ( - 18 ) - 12 5}{2 \cdot 3}

x = \frac{- ( - 18 ) + 12 5}{2 \cdot 3} : 3 + 25

x = \frac{- ( - 18 ) - 12 5}{2 \cdot 3} : 3 - 25

The solutions to the quadratic equation are:

x = 3 + 25, x = 3 - 25

k^{2} + 4 k - 95 = - 8

2 x^{2} - 14 x + 12 = 0

4 x^{2} + 27 x - 40 = 0

x^{2} + 20 x + 100 = 81

3 (g - 1)^{2} + 2 = 0

What are the solutions to the equation 3x^2-33=18x ?
The solutions to the equation 3x^2-33=18x are x=3+2sqrt(5),x=3-2sqrt(5)
Find the zeros of 3x^2-33=18x
The zeros of 3x^2-33=18x are x=3+2sqrt(5),x=3-2sqrt(5)