What are the solutions to the equation x^2=9^2+4^2 ?

The solutions to the equation x^2=9^2+4^2 are x=sqrt(97),x=-sqrt(97)

Find the zeros of x^2=9^2+4^2

The zeros of x^2=9^2+4^2 are x=sqrt(97),x=-sqrt(97)

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x^{2} = 9^{2} + 4^{2}

x = 97, x = - 97

Decimal Notation

x = 9.84885 \dots, x = - 9.84885 \dots

Solution steps

x^{2} = 9^{2} + 4^{2}

Simplify

9^{2} + 4^{2} : 97

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 97, x = - 97

5 x^{2} = 210 x

x^{2} - 10 x + 12 = 0

\frac{x ^{2} - 3 x}{2} - 5 = \frac{x - 20}{4}

2 x^{2} + 7 x - 9 = - 5

x^{2} + 0.54 x - 0.27 = 0

What are the solutions to the equation x^2=9^2+4^2 ?
The solutions to the equation x^2=9^2+4^2 are x=sqrt(97),x=-sqrt(97)
Find the zeros of x^2=9^2+4^2
The zeros of x^2=9^2+4^2 are x=sqrt(97),x=-sqrt(97)