What are the solutions to the equation 1-3/4 x+1/8 x^2=0 ?

The solutions to the equation 1-3/4 x+1/8 x^2=0 are x=4,x=2

Find the zeros of 1-3/4 x+1/8 x^2=0

The zeros of 1-3/4 x+1/8 x^2=0 are x=4,x=2

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1 - \frac{3}{4} x + \frac{1}{8} x^{2} = 0

x = 4, x = 2

Solution steps

1 - \frac{3}{4} x + \frac{1}{8} x^{2} = 0

Find Least Common Multiplier of

4, 8 : 8

Multiply by LCM=

8

1 \cdot 8 - \frac{3}{4} x \cdot 8 + \frac{1}{8} x^{2} \cdot 8 = 0 \cdot 8

Simplify

x^{2} - 6 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 8 = 2

x_{1, 2} = \frac{- ( - 6 ) \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 2}{2 \cdot 1}

x = \frac{- ( - 6 ) + 2}{2 \cdot 1} : 4

x = \frac{- ( - 6 ) - 2}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

x = 4, x = 2

x^{2} - 155 x + 6000 = 0

x^{2} + 3^{2} = 2^{2}

x, y - ln (y) = x^{2} + 1

4 - 2 x^{2} = 12

14.59 \cdot 0.6 \cdot t - \frac{1}{2} \cdot 5 \cdot t^{2} = 1

What are the solutions to the equation 1-3/4 x+1/8 x^2=0 ?
The solutions to the equation 1-3/4 x+1/8 x^2=0 are x=4,x=2
Find the zeros of 1-3/4 x+1/8 x^2=0
The zeros of 1-3/4 x+1/8 x^2=0 are x=4,x=2