What are the solutions to the equation x^2-155x+6000=0 ?

The solutions to the equation x^2-155x+6000=0 are x=80,x=75

Find the zeros of x^2-155x+6000=0

The zeros of x^2-155x+6000=0 are x=80,x=75

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x^{2} - 155 x + 6000 = 0

x = 80, x = 75

Solution steps

x^{2} - 155 x + 6000 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 155 ) \pm ( - 155 ) ^{2} - 4 \cdot 1 \cdot 6000}{2 \cdot 1}

(- 155)^{2} - 4 \cdot 1 \cdot 6000 = 5

x_{1, 2} = \frac{- ( - 155 ) \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 155 ) + 5}{2 \cdot 1}, x_{2} = \frac{- ( - 155 ) - 5}{2 \cdot 1}

x = \frac{- ( - 155 ) + 5}{2 \cdot 1} : 80

x = \frac{- ( - 155 ) - 5}{2 \cdot 1} : 75

The solutions to the quadratic equation are:

x = 80, x = 75

x^{2} + 3^{2} = 2^{2}

x, y - ln (y) = x^{2} + 1

4 - 2 x^{2} = 12

14.59 \cdot 0.6 \cdot t - \frac{1}{2} \cdot 5 \cdot t^{2} = 1

y, 4 x^{2} + y^{2} = 4

What are the solutions to the equation x^2-155x+6000=0 ?
The solutions to the equation x^2-155x+6000=0 are x=80,x=75
Find the zeros of x^2-155x+6000=0
The zeros of x^2-155x+6000=0 are x=80,x=75