What are the solutions to the equation solvefor x,9x^2+3x-1=0 ?

The solutions to the equation solvefor x,9x^2+3x-1=0 are x=(-1+sqrt(5))/6 ,x=-(1+sqrt(5))/6

Find the zeros of solvefor x,9x^2+3x-1=0

The zeros of solvefor x,9x^2+3x-1=0 are x=(-1+sqrt(5))/6 ,x=-(1+sqrt(5))/6

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x, 9 x^{2} + 3 x - 1 = 0

x = \frac{- 1 + 5}{6}, x = - \frac{1 + 5}{6}

Decimal Notation

x = 0.20601 \dots, x = - 0.53934 \dots

Solution steps

9 x^{2} + 3 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 9 ( - 1 )}{2 \cdot 9}

3^{2} - 4 \cdot 9 (- 1) = 35

x_{1, 2} = \frac{- 3 \pm 3 5}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 3 + 3 5}{2 \cdot 9}, x_{2} = \frac{- 3 - 3 5}{2 \cdot 9}

x = \frac{- 3 + 3 5}{2 \cdot 9} : \frac{- 1 + 5}{6}

x = \frac{- 3 - 3 5}{2 \cdot 9} : - \frac{1 + 5}{6}

The solutions to the quadratic equation are:

x = \frac{- 1 + 5}{6}, x = - \frac{1 + 5}{6}

(x + 6) (x + 4) = 0

4 x^{2} - 48 x + 335 = 7

260 + 13 x - 13 x^{2} = 13 x^{2} - 65 x

- \frac{1}{2} (x + 1)^{2} + 8 = - 1

x^{2} + 2 x + 63 = 0

What are the solutions to the equation solvefor x,9x^2+3x-1=0 ?
The solutions to the equation solvefor x,9x^2+3x-1=0 are x=(-1+sqrt(5))/6 ,x=-(1+sqrt(5))/6
Find the zeros of solvefor x,9x^2+3x-1=0
The zeros of solvefor x,9x^2+3x-1=0 are x=(-1+sqrt(5))/6 ,x=-(1+sqrt(5))/6