What are the solutions to the equation 260+13x-13x^2=13x^2-65x ?

The solutions to the equation 260+13x-13x^2=13x^2-65x are x=-2,x=5

Find the zeros of 260+13x-13x^2=13x^2-65x

The zeros of 260+13x-13x^2=13x^2-65x are x=-2,x=5

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260 + 13 x - 13 x^{2} = 13 x^{2} - 65 x

x = - 2, x = 5

Solution steps

260 + 13 x - 13 x^{2} = 13 x^{2} - 65 x

Move

65 x

to the left side

- 13 x^{2} + 78 x + 260 = 13 x^{2}

Move

13 x^{2}

to the left side

- 26 x^{2} + 78 x + 260 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 78 \pm 7 8 ^{2} - 4 ( - 26 ) \cdot 260}{2 ( - 26 )}

7 8^{2} - 4 (- 26) \cdot 260 = 182

x_{1, 2} = \frac{- 78 \pm 182}{2 ( - 26 )}

Separate the solutions

x_{1} = \frac{- 78 + 182}{2 ( - 26 )}, x_{2} = \frac{- 78 - 182}{2 ( - 26 )}

x = \frac{- 78 + 182}{2 ( - 26 )} : - 2

x = \frac{- 78 - 182}{2 ( - 26 )} : 5

The solutions to the quadratic equation are:

x = - 2, x = 5

- \frac{1}{2} (x + 1)^{2} + 8 = - 1

x^{2} + 2 x + 63 = 0

4 x^{2} + 20 x = 2

0 = 3 x^{2} - 36 x + 81

2 n^{2} + 2 n - 84 = 0

What are the solutions to the equation 260+13x-13x^2=13x^2-65x ?
The solutions to the equation 260+13x-13x^2=13x^2-65x are x=-2,x=5
Find the zeros of 260+13x-13x^2=13x^2-65x
The zeros of 260+13x-13x^2=13x^2-65x are x=-2,x=5