What are the solutions to the equation 6=x^2-5x ?

The solutions to the equation 6=x^2-5x are x=6,x=-1

Find the zeros of 6=x^2-5x

The zeros of 6=x^2-5x are x=6,x=-1

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6 = x^{2} - 5 x

x = 6, x = - 1

Solution steps

6 = x^{2} - 5 x

Switch sides

x^{2} - 5 x = 6

Move

6

to the left side

x^{2} - 5 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 6) = 7

x_{1, 2} = \frac{- ( - 5 ) \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 7}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 7}{2 \cdot 1}

x = \frac{- ( - 5 ) + 7}{2 \cdot 1} : 6

x = \frac{- ( - 5 ) - 7}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 6, x = - 1

3 x^{2} + 6 x + 3

- 31 z = - 49 z^{2}

x^{2} + 4 x + c = 0

5 x^{2} - 3 x + a - 1 = 0.7

x, x^{2} + y^{2} + 4 x - 3 y + 9 = 0

What are the solutions to the equation 6=x^2-5x ?
The solutions to the equation 6=x^2-5x are x=6,x=-1
Find the zeros of 6=x^2-5x
The zeros of 6=x^2-5x are x=6,x=-1