What are the solutions to the equation -16t^2+100=0 ?

The solutions to the equation -16t^2+100=0 are t= 5/2 ,t=-5/2

Find the zeros of -16t^2+100=0

The zeros of -16t^2+100=0 are t= 5/2 ,t=-5/2

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- 16 t^{2} + 100 = 0

t = \frac{5}{2}, t = - \frac{5}{2}

Decimal Notation

t = 2.5, t = - 2.5

Solution steps

- 16 t^{2} + 100 = 0

Move

100

to the right side

- 16 t^{2} = - 100

Divide both sides by

- 16

t^{2} = \frac{25}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = \frac{25}{4}, t = - \frac{25}{4}

\frac{25}{4} = \frac{5}{2}

- \frac{25}{4} = - \frac{5}{2}

t = \frac{5}{2}, t = - \frac{5}{2}

\frac{785}{16} = - 16 (t)^{2} + 50 (t) + 10

32 = - 16 t^{2} + 16 t + 32

s^{2} = 2

x^{2} + 16 x = - 8

u^{2} + 4 u - 5 = 0

What are the solutions to the equation -16t^2+100=0 ?
The solutions to the equation -16t^2+100=0 are t= 5/2 ,t=-5/2
Find the zeros of -16t^2+100=0
The zeros of -16t^2+100=0 are t= 5/2 ,t=-5/2