What are the solutions to the equation solvefor x,x^2+4x+7=0 ?

The solutions to the equation solvefor x,x^2+4x+7=0 are x=-2+sqrt(3)i,x=-2-sqrt(3)i

Find the zeros of solvefor x,x^2+4x+7=0

The zeros of solvefor x,x^2+4x+7=0 are x=-2+sqrt(3)i,x=-2-sqrt(3)i

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x, x^{2} + 4 x + 7 = 0

x = - 2 + 3 i, x = - 2 - 3 i

Solution steps

x^{2} + 4 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

Simplify

4^{2} - 4 \cdot 1 \cdot 7 : 23 i

x_{1, 2} = \frac{- 4 \pm 2 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 2 3 i}{2 \cdot 1}, x_{2} = \frac{- 4 - 2 3 i}{2 \cdot 1}

x = \frac{- 4 + 2 3 i}{2 \cdot 1} : - 2 + 3 i

x = \frac{- 4 - 2 3 i}{2 \cdot 1} : - 2 - 3 i

The solutions to the quadratic equation are:

x = - 2 + 3 i, x = - 2 - 3 i

x^{2} - 2 - 3 = 0

x^{2} + 8 x - 64 = 0

3 (x + 1)^{2} - 48 = 0

X, Y = X^{2} - 4 X + 3

- 7 x^{2} + 7 x + 140 = 0

What are the solutions to the equation solvefor x,x^2+4x+7=0 ?
The solutions to the equation solvefor x,x^2+4x+7=0 are x=-2+sqrt(3)i,x=-2-sqrt(3)i
Find the zeros of solvefor x,x^2+4x+7=0
The zeros of solvefor x,x^2+4x+7=0 are x=-2+sqrt(3)i,x=-2-sqrt(3)i