What are the solutions to the equation solvefor x,x^2+y^2-8x+27-8=0 ?

The solutions to the equation solvefor x,x^2+y^2-8x+27-8=0 are x=4+sqrt(-y^2-3),x=4-sqrt(-y^2-3)

Find the zeros of solvefor x,x^2+y^2-8x+27-8=0

The zeros of solvefor x,x^2+y^2-8x+27-8=0 are x=4+sqrt(-y^2-3),x=4-sqrt(-y^2-3)

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solve for

x, x^{2} + y^{2} - 8 x + 27 - 8 = 0

x = 4 + - y^{2} - 3, x = 4 - - y^{2} - 3

Solution steps

x^{2} + y^{2} - 8 x + 27 - 8 = 0

Expand

x^{2} + y^{2} - 8 x + 27 - 8 : x^{2} - 8 x + y^{2} + 19

x^{2} - 8 x + y^{2} + 19 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot ( y ^{2} + 19 )}{2 \cdot 1}

Simplify

(- 8)^{2} - 4 \cdot 1 \cdot (y^{2} + 19) : 2 - y^{2} - 3

x_{1, 2} = \frac{- ( - 8 ) \pm 2 - y ^{2} - 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 - y ^{2} - 3}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 2 - y ^{2} - 3}{2 \cdot 1}

x = \frac{- ( - 8 ) + 2 - y ^{2} - 3}{2 \cdot 1} : 4 + - y^{2} - 3

x = \frac{- ( - 8 ) - 2 - y ^{2} - 3}{2 \cdot 1} : 4 - - y^{2} - 3

The solutions to the quadratic equation are:

x = 4 + - y^{2} - 3, x = 4 - - y^{2} - 3

x^{2} + 4 - 2 x = 0

x^{2} + x - 6 = 6

a, x^{2} + (y - a)^{2} = 25

x, x^{2} - 4 x = - 4

n^{2} + 4 n = 32

What are the solutions to the equation solvefor x,x^2+y^2-8x+27-8=0 ?
The solutions to the equation solvefor x,x^2+y^2-8x+27-8=0 are x=4+sqrt(-y^2-3),x=4-sqrt(-y^2-3)
Find the zeros of solvefor x,x^2+y^2-8x+27-8=0
The zeros of solvefor x,x^2+y^2-8x+27-8=0 are x=4+sqrt(-y^2-3),x=4-sqrt(-y^2-3)