What are the solutions to the equation v^2-3v-18=0 ?

The solutions to the equation v^2-3v-18=0 are v=6,v=-3

Find the zeros of v^2-3v-18=0

The zeros of v^2-3v-18=0 are v=6,v=-3

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v^{2} - 3 v - 18 = 0

v = 6, v = - 3

Solution steps

v^{2} - 3 v - 18 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 18 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 18) = 9

v_{1, 2} = \frac{- ( - 3 ) \pm 9}{2 \cdot 1}

Separate the solutions

v_{1} = \frac{- ( - 3 ) + 9}{2 \cdot 1}, v_{2} = \frac{- ( - 3 ) - 9}{2 \cdot 1}

v = \frac{- ( - 3 ) + 9}{2 \cdot 1} : 6

v = \frac{- ( - 3 ) - 9}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

v = 6, v = - 3

t, u = t^{2} + 2

18 = 0.9 x^{2} - 3 x + 3

x^{2} + 4 x + 6 = 0

5 + 4 x - x^{2}

x^{2} + (- x)^{2} = 1

What are the solutions to the equation v^2-3v-18=0 ?
The solutions to the equation v^2-3v-18=0 are v=6,v=-3
Find the zeros of v^2-3v-18=0
The zeros of v^2-3v-18=0 are v=6,v=-3