What are the solutions to the equation 1/4 r^2+3r+8=0 ?

The solutions to the equation 1/4 r^2+3r+8=0 are r=-4,r=-8

Find the zeros of 1/4 r^2+3r+8=0

The zeros of 1/4 r^2+3r+8=0 are r=-4,r=-8

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\frac{1}{4} r^{2} + 3 r + 8 = 0

r = - 4, r = - 8

Solution steps

\frac{1}{4} r^{2} + 3 r + 8 = 0

Multiply both sides by

4

r^{2} + 12 r + 32 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot 32}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot 32 = 4

r_{1, 2} = \frac{- 12 \pm 4}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- 12 + 4}{2 \cdot 1}, r_{2} = \frac{- 12 - 4}{2 \cdot 1}

r = \frac{- 12 + 4}{2 \cdot 1} : - 4

r = \frac{- 12 - 4}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

r = - 4, r = - 8

4 x^{2} + 9 x = 22

3.639 = π \cdot \frac{x ^{2}}{4} \cdot 2.2

x^{2} + 8 x - 96 = 0

- 26 x + 8 x^{2} = 24

3 x^{2} + 9 x - 7 = 0

What are the solutions to the equation 1/4 r^2+3r+8=0 ?
The solutions to the equation 1/4 r^2+3r+8=0 are r=-4,r=-8
Find the zeros of 1/4 r^2+3r+8=0
The zeros of 1/4 r^2+3r+8=0 are r=-4,r=-8