What are the solutions to the equation solvefor x,4x^2-12xy+9y^2=0 ?

The solutions to the equation solvefor x,4x^2-12xy+9y^2=0 are x=(3y)/2

Find the zeros of solvefor x,4x^2-12xy+9y^2=0

The zeros of solvefor x,4x^2-12xy+9y^2=0 are x=(3y)/2

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solve for

x, 4 x^{2} - 12 x y + 9 y^{2} = 0

x = \frac{3 y}{2}

Solution steps

4 x^{2} - 12 x y + 9 y^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} - 12 y x + 9 y^{2} = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 y ) \pm ( - 12 y ) ^{2} - 4 \cdot 4 \cdot 9 y ^{2}}{2 \cdot 4}

(- 12 y)^{2} - 4 \cdot 4 \cdot 9 y^{2} = 0

x_{1, 2} = \frac{- ( - 12 y ) \pm 0}{2 \cdot 4}

x = \frac{- ( - 12 y )}{2 \cdot 4}

Simplify

\frac{- ( - 12 y )}{2 \cdot 4} : \frac{3 y}{2}

x = \frac{3 y}{2}

The solution to the quadratic equation is:

x = \frac{3 y}{2}

k^{2} + 9 k + 14 = 0

- 32 x^{2} + 98 = 0

3 z^{2} + 6 z + 3 = 0

r, r^{2} - 2 r + 2 = 0

x = \frac{1}{2} (0.004) (5 - 5000 x - 0.3)^{2}

What are the solutions to the equation solvefor x,4x^2-12xy+9y^2=0 ?
The solutions to the equation solvefor x,4x^2-12xy+9y^2=0 are x=(3y)/2
Find the zeros of solvefor x,4x^2-12xy+9y^2=0
The zeros of solvefor x,4x^2-12xy+9y^2=0 are x=(3y)/2