What are the solutions to the equation 6x^2-130x+500=0 ?

The solutions to the equation 6x^2-130x+500=0 are x= 50/3 ,x=5

Find the zeros of 6x^2-130x+500=0

The zeros of 6x^2-130x+500=0 are x= 50/3 ,x=5

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6 x^{2} - 130 x + 500 = 0

x = \frac{50}{3}, x = 5

Decimal Notation

x = 16.66666 \dots, x = 5

Solution steps

6 x^{2} - 130 x + 500 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 130 ) \pm ( - 130 ) ^{2} - 4 \cdot 6 \cdot 500}{2 \cdot 6}

(- 130)^{2} - 4 \cdot 6 \cdot 500 = 70

x_{1, 2} = \frac{- ( - 130 ) \pm 70}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 130 ) + 70}{2 \cdot 6}, x_{2} = \frac{- ( - 130 ) - 70}{2 \cdot 6}

x = \frac{- ( - 130 ) + 70}{2 \cdot 6} : \frac{50}{3}

x = \frac{- ( - 130 ) - 70}{2 \cdot 6} : 5

The solutions to the quadratic equation are:

x = \frac{50}{3}, x = 5

D^{2} + 2 D + 1 = 0

2 d = a t^{2}

k^{2} - 4 k + 69 = - 3

x^{2} - 25 = 12, x + 5 = 4, x - 5

x^{2} - 10 x + 25 = - 16 + 25

What are the solutions to the equation 6x^2-130x+500=0 ?
The solutions to the equation 6x^2-130x+500=0 are x= 50/3 ,x=5
Find the zeros of 6x^2-130x+500=0
The zeros of 6x^2-130x+500=0 are x= 50/3 ,x=5