What are the solutions to the equation 2d=at^2 ?

The solutions to the equation 2d=at^2 are t=sqrt((2d)/a),t=-sqrt((2d)/a);\quad a\ne 0

Find the zeros of 2d=at^2

The zeros of 2d=at^2 are t=sqrt((2d)/a),t=-sqrt((2d)/a);\quad a\ne 0

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2 d = a t^{2}

t = \frac{2 d}{a}, t = - \frac{2 d}{a}; a \neq = 0

Solution steps

2 d = a t^{2}

Switch sides

a t^{2} = 2 d

Divide both sides by

a; a \neq = 0

t^{2} = \frac{2 d}{a}; a \neq = 0

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = \frac{2 d}{a}, t = - \frac{2 d}{a}; a \neq = 0

k^{2} - 4 k + 69 = - 3

x^{2} - 25 = 12, x + 5 = 4, x - 5

x^{2} - 10 x + 25 = - 16 + 25

\frac{- 1}{6} x^{2} + x - 3 = 0

- 21 x^{2} + 31 x + 26 = 0

What are the solutions to the equation 2d=at^2 ?
The solutions to the equation 2d=at^2 are t=sqrt((2d)/a),t=-sqrt((2d)/a);\quad a\ne 0
Find the zeros of 2d=at^2
The zeros of 2d=at^2 are t=sqrt((2d)/a),t=-sqrt((2d)/a);\quad a\ne 0